72v^2+73v+16=v

Solution for 72v^2+73v+16=v equation:

72v^2+73v+16=v

We move all terms to the left:

72v^2+73v+16-(v)=0

We add all the numbers together, and all the variables

72v^2+72v+16=0

a = 72; b = 72; c = +16;
Δ = b2-4ac
Δ = 722-4·72·16
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-24}{2*72}=\frac{-96}{144}
=-2/3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+24}{2*72}=\frac{-48}{144}
=-1/3
$